If the polynomial:x⁴+2x³+8x²+12x+8 is divided by another polynomial (x²+5) the remainder is (ax+b) find a-b
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x⁴+2x³+8x²+12x+8 is divided by x²+5
then, x²+5=0
x²=-5
X=√-5
=(√-5)⁴+2(√-5)³+8(√-5)²+12(√-5)+8
=25-10√-5-40+12√-5+8
=25+8-40-10√-5+12√-5
=-7+2√-5
=2√-5 -7
X=√-5
a=2
b=7
ax+b=2×√-5+7
a - b = 2-(-7) = 9
then, x²+5=0
x²=-5
X=√-5
=(√-5)⁴+2(√-5)³+8(√-5)²+12(√-5)+8
=25-10√-5-40+12√-5+8
=25+8-40-10√-5+12√-5
=-7+2√-5
=2√-5 -7
X=√-5
a=2
b=7
ax+b=2×√-5+7
a - b = 2-(-7) = 9
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