If the polynomialax3+4x2+3x-4 and x3-4x+a leaves the same remainder when divided by x-3, find the value of a
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The both eqn as same remainder.so
ax^3+4x^2+3x-4=x^3-4x+a
x-3=0
x=3-----(1)
from eqn 1
27a+36+9-4=27-12+a
27a+41=15+a
27a-a=15-41
26a=-26
a=-1
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