Question

if the polynomials 2 x cube + a x square plus 3 x minus 5 and x cube + 2 x square minus 5 minus A leave the same remainder when divided by x minus 1 then find the value of a​

Answer 1

Answer:

a=-1.

Hope it helps you

Answer 2

Answer:

a=-1

P(x)-2x3tax^2+3x-5

p(x) is divided by x-1

Remainder 2(13+ a(1)^2+3x1-5

=2ta+3-5

a

Again, q(x) = x^3 + 2x^2 - 5x - a

Since, qx) is divided by x-1 then

Remainder = (13+ 2(1^2 5x 1- a

= 1+2-5-a

-2-a

A/Q

Since, Both remainder are equal

Therefore, a = -2-a

2a=-2

a = -1.