if the polynomials (2x3+ax2+3x-5) and(cx3+x2-2x+3) leave remainder r1 and r2 when divided by (x-2) such that r1 =r2, find a
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Answer:
-13/3
Step-by-step explanation:
f(2) = g(2)
2x³ + ax² + 3x – 5 = x³ + x² -4x + a
2(2)³ + a(2)² + 3(2) – 5 = 2³ + 2² – 4(2) + a
2(8) + a(4) + 6 – 5 = 8 + 4 – 8 + a
16 + 4a + 1 = 4 + a
17 + 4a = 4 + a
4a – a = 4 – 17
3a = -13
a = -13/3.
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