If the polynomials (2x3 +ax2 +3x -5) and (x3 + x2 –4x + a) leave the same remainder
when divided by (x – 2), find the value of ‘a’.
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Step-by-step explanation:
Given polynomial ,
p(x) = 2x^3 + ax^2 +3x-5
and , f(x)= x^3+x^2-4x+a
Using remainder theorem ,
p(2)= f(2)
→2(2)^3 + 4a +6-5= (2)^3+(2)^2-8+a
→16 + 4a +1= 8+4-8+a
→3a = 4-16-1= -13
→ a= -13/3
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