If the polynomials a x^3 + 3 x^2 - 13 and 2 x^3 - 5 x + a leave the same remainder when divided by x + 2 . Find the value of a. *
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Step-by-step explanation:
f(x)=ax3+3x2−13
g(x)=2x3−5x+9
x−2=0
x=2
a23+3⋅22−13=2⋅23−5⋅2+9
8a+12−13=16−10+9
7a=6+1
7a=7
a=1.
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