If the polynomials ax^3 + 4x^2 3x -4 and x^3 - 4x +a leave the same remainder when devided by (x-3) find value of a
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Answer:
Step-by-step explanation:
x-3=0
x=3
a*3^3+4*3^2+3*3-4=3^3-4*3+a
27a+36+9-4=27-12+a
27a+41=15+a
27a-a=15-41
26a= -26
a= -26/26
a= -1
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