Question

If the polynomials px3 + 4x2 +3x – 4 and x3 – 4x + p are divided by x -3 then the

remainder in each case is the same. Find the value of p.​

Answer 1

Answer:

Step-by-step explanation:

let f(x)=px³ + 4x² +3x – 4

and g(x) =x³-4x+p

When f(x) is divided by x -3

Then Remainder R=27p+9*4+3*3-4

=27p+41

When g(x) is divided by x -3

Then Remainder R'=27-3*4+p

R'=15+p

Now R=R'

27p+41=15+p

26p=26

p=1