if the polynomials
and
are divided by x+2 leave the same remainder, find the value of a.
Answers
Answered by
0
a= -13/3 .. is it ri8
Answered by
2
Here,
p(x) = x³ + ax² + 5
g(x) = x³ - 2x² + a
p and g are divided by (x+2),
so by remainder theorem,
p(-2) = g(-2) = remainders
=>
(-2)³ + a·(-2)² + 5 = (-2)³ - 2·(-2)² + a
or
-8 + 4a + 5 = -8 - 8 + a
or
3a = -13
a = -13/3
hope it helps you if yes then please mark my answer as brainliest ☺️☺️
p(x) = x³ + ax² + 5
g(x) = x³ - 2x² + a
p and g are divided by (x+2),
so by remainder theorem,
p(-2) = g(-2) = remainders
=>
(-2)³ + a·(-2)² + 5 = (-2)³ - 2·(-2)² + a
or
-8 + 4a + 5 = -8 - 8 + a
or
3a = -13
a = -13/3
hope it helps you if yes then please mark my answer as brainliest ☺️☺️
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