Question

If the polynomials x^3+6x^2 +4x+k is divisible by (x+2 ),then the value of k​

Answer 1

Step-by-step explanation:

since the polynomial is divisible the x+2 will be its factor.

x+2=0

x=-2

on putting value of x the polynomial becomes equal to 0

(-2)^3+6(-2)^2+4×(-2)+k=0

-8+24-8+k=0

24-16=k

k=-8

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Answer 2

Answer:

x+2=0 (GIVEN)

x=-2

Given polynomial (x^3+6x^2+4x+k)

By putting values of x,

=(-2)^3+6(-2)^2+4(-2)+k=0

=-8+24-8+k=0

=8+k=0

=k=-8

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