If the polynomials x^3+6x^2 +4x+k is divisible by (x+2 ),then the value of k
Answers
Answered by
0
Step-by-step explanation:
since the polynomial is divisible the x+2 will be its factor.
x+2=0
x=-2
on putting value of x the polynomial becomes equal to 0
(-2)^3+6(-2)^2+4×(-2)+k=0
-8+24-8+k=0
24-16=k
k=-8
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Answered by
1
Answer:
x+2=0 (GIVEN)
x=-2
Given polynomial (x^3+6x^2+4x+k)
By putting values of x,
=(-2)^3+6(-2)^2+4(-2)+k=0
=-8+24-8+k=0
=8+k=0
=k=-8
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