If the polynomials x3+ax2+5 and (x3-2x2+a) leave the same remainder when divided by (x-2) find the value of a
Answers
Answered by
58
Answer:
Value of a is -13/3.
Step-by-step explanation:
Given:
Polynomials are x³ +ax² + 5 and x³ - 2x² + a
Polynomials divided by x - 2 leaves same remainder.
To find: value of a.
We use Remainder theorem which states that When a polynomial p(x) is divided by linear polynomial of the form x - a then remainder is equal to p(a).
let, p(x) = x³ + ax² + 5 and g(x) = x³ - 2x² + a
According to the question,
p(2) = g(2)
(2)³ + a(2)² + 5 = (2)³ - 2(2)² + a
8 + 4a + 5 = 8 - 8 + a
4a + 13 = a
3a = -13
a = -13/3
Therefore, Value of a is -13/3.
Answered by
17
Answer:
Here is your answer
Step-by-step explanation:
Attachments:
Similar questions