Question

If the polynomials2x³+kx²+3x-5 and x³+x² -2x+2k leave same remainder when divided by x-3. Find the value of k.


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Answer 1

Answer:

k= -4

Step-by-step explanation:

by remainder theorem when p (x) is divided by x-3 then the remainder is p (3)

p (x)= 2x^3+kx^2+3x-5

p(3)=2 (3)^3+k (3)^2+3 (3)-5

54+4+9k

58+9k this the remainder(1)

by remainder theorem when f (x) is divided by x-3 then the remainder is f (3)

f (x)=x^3+x^2x+2k

f (3)=(3)^3+(3)^2-2 (3)+2k

36-6+2k

30+2k this the remainder (2)

it is given that the remainders are same

(1)=(2)

58+9k=30+2k

58-30=2k-9k

28= -7k

k= -4

here is the correct answer

Answer 2

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