if the population growth rate of a city in Nepal has 4%after how many years the population of the city will be doubled
Answers
Answered by
5
Answer:
dt
dp
∝p
⟹
dt
dp
=kp (where k is constant)
⟹∫
dt
dp
=∫kdt
⟹lnp=kt+c (on integrating both sides)
At t=0,p=(1/2)lac=50,000.
At t=25,p=(1/2)lac=1,00,000.
∴ we get, c=ln(50,000) and k=ln(2)/25
∴ For P=4,00,000
lnp=
25
ln(2)
t+ln(50,000)
ln(4,00,000)=
25
ln(2)
t+ln(50,000)
Solving for t, we get t=75.
Now as we have assumed t=0 after 25 years. So, city have population of 4,00,000 before 25 years.
Hence time =75−25=50years
Answered by
0
Answer:
100÷4
.= 25
so answer is 25 years
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