Question

If the population of a town decreases 6.25% annually and the present population is

20480000, find its population after 3 years.

(A) 16875000 (B) 16175000

(C) 14875000 (D) 14175000

Answer 1

population of town=20480000. population of town decreases=6.25%
amount=(1-R/100)³
=20480000(1-6.25/100)³
=20480000(9375/10000)³
=16875000



option a is correct


hope is correct please reply

Answer 2

$\tiny \: \blue{ \mathsf{ \huge{Given:}}}$

$\tiny \: \green{ \mathsf{ \bf{Population \: of \: \: a \: \: town \: \: decreases \: \: 6.25\% \: \: annually}}}$

$\tiny \: \red{ \mathsf{ \bf{Present \: \: \: Population \: \: = \: \: 20480000,}}}$

$\tiny \: \orange{ \mathsf{ \huge{To \: \: Find :}}}$

$\tiny \: \red{ \mathsf{ \bf{Population \: \: after \: \: 3 \: \: Years.}}}$

$\tiny \: \orange{ \mathsf{ \huge{ Method \: of \: Solution :}}}$

$\tiny \: \red{ \mathsf{ \bf{Required \: \: Population = ({1 - {\frac{d}{100 }^{2})}}}}} \: \:$

$\tiny \: \green{ \mathsf{ \bf{Required \: \: Population = 20480000 \: \: ( {1 - {\frac{6.25}{100 }^{3})}}}}}$

$\tiny \: \blue{ \mathsf{ \bf{Required \: \: Population = 20480000 \: \: ( {1 - {\frac{625}{10000 }^{3})}}}}}$

$\tiny \: \green{ \mathsf{ \bf{Required \: \: Population = 20480000 \: \: ( {1 - {\frac{1}{16}^{3})}}}}}$
$\tiny \: \red{ \mathsf{ \fbox{ \fbox{ \bf{Hence, \: \: \: Required \: \: \: Population = 16875000}}}}}$