Question

if the population of a town increased by 10% annually the present population is 22000,find its population a year ago

Answer 1

let 'x' represent the population a year ago

x + 0.10x = 22000

x(1 + 0.10) = 22000

x*1.10 = 22000 divide both sides by 1.10

x = 22000/1.10

x = 20,000

the population was 20,000 one year ago.

Answer 2

let the population of the town year ago is x.
so present population = X + 10% of X
= 11x/10
but the present population is 22000
then, 11x/10 = 22000
x = 20000