Question

If The Population Of A Town Increases 2% Annually And The Present Population Is 3,26,40,000, Find Its Population After 2 Years.

Answer 1

Answer:

$3,26,40,000$

Step-by-step explanation:

Given data:

• The population of a town increases $2$% annually.

• The present population is $3,26,40,000$

• We can find the population after $2$ years by using the population formula.

• Population of the town after two years

$=3,26,40,000(1+\frac{2}{100})^{2}$

$=3,26,40,000\times\frac{51}{50} \times\frac{51}{50}$

$=3,39,58,656$

Hence, the population after $2$ years will be $3,26,40,000$.

Answer 2

Given :

• Present population = 3,26,40,000
• Increasing Rate = 2 %

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To Find :

• Population after 2 years = ?

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Solution :

~ Formula Used :

$\large{\blue{\dashrightarrow}} \: \: {\underline{\boxed{\red{\sf{ A = P \bigg( 1 + \dfrac{R}{100} \bigg)^T }}}}}$

Where :

• ➳ A = Population after 2 years
• ➳ P = Present population
• ➳ R = Increasing Rate
• ➳ T = Time

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~ Calculating the Population after 2 years :

${\longmapsto{\qquad{\sf{ A = P \bigg( 1 + \dfrac{R}{100} \bigg)^T }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ A = 32640000 \bigg( 1 + \dfrac{2}{100} \bigg)^2 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ A = 32640000 \bigg( 1 + \cancel\dfrac{2}{100} \bigg)^2 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ A = 32640000 \bigg( 1 + 0.02 \bigg)^2 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ A = 32640000 \bigg( 1.02 \bigg)^2 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ A = 32640000 \times 1.02 \times 1.02 }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ A = 32640000 \times 1.0404 }}}} \\ \\ \ {\qquad{\textsf{ Population after 2 years = {\purple{\sf{ 33958656 }}}}}}$

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Therefore :

❝ After 2 years, the population of the town will be 3,39,58,656 .❞

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