Question

If the position of a particle varies with time, given
by x = (2t ^2+ 6t + 7) m, then what will be its
acceleration at t = 1 s?​

Answer 1

Answer:

4 m/s^2

Explanation:

Velocity = dx/dt

by differentiation you will get v = 4t + 6

Now

as acceleration = dv/dt

By differentiating you will get a = 4