Question

if the position of electron is measured within an accuracy of +- 0.002 nm calculate the uncertainly in the momentum of electron

Answer 1

Explanation:

By applying the uncertainty principle,

ΔP=

4πΔx

h

=

4×3.1416×0.002×10

−9

6.626×10

−34

=2.63×10

−23

kg m/s

The uncertainty in momentum is,

4πm×0.002×10

−9

h

=

4×π×m

h×5×10

11

.

This is much larger than the actual momentum, i.e,

4πm

h

×0.05 nm. Hence, it cannot be defined.