If the position of he electron is measured wth an accuracy
Answers
Answered by
1
Explanation:
From Heisenberg’s uncertainty principle,
Where,
Δx = uncertainty in position of the electron
Δp = uncertainty in momentum of the electron
Δx = 0.002nm = 2x10-12m(given)
Therefore, Substituting the values in the expression of Δp:
Δp = h/4π Δx or
= 2.637 × 10–23 Jsm–1
Δp = 2.637 × 10–23 kgms–1 (1 J = 1 kgms2s–1)
Actual momentum = h/4πx 0.05nm
= 6.626x10-34/4 x3.14 x 5 x10-11
= 1.055 x 10-24 kg m/sec
Answered by
0
Answer:
If the position of an electron is measured with accuracy then its momentum cannot be measured accurately in accordance to Heisenberg's Uncertainty Principle.
Similar questions