Question

If the position of the particle at instant 't' is given by x = 2t^3 , find the acceleration of the particle.

Answer 1

Answer:

answer is 12t .............

Answer 2

Answer:

12t

Explanation:

distance= x = 2t^3

time = t

acceleration = ?

First we find the velocity ,

To find velocity from distance.. we do differentiation

Velocity = dx/dt

= d(2t^3)/ dt

= 2(3t^2)

= 6t^2

Then we find acceleration,

To find acceleration from velocity.. we do differentiation

Acceleration = dv/dt

= d(6t^2)/dt

= 6(2t)

= 12t