Question

If the position of the particle is given by y=kt^3. if k is constant then

options
a)acceleration is constant
b)displacement is constant
c)acceleration vary with time
d)acceleration is zero
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Answer 1

Answer:

The answer is displacement is constant

Answer 2

Answer:

Option (c) acceleration vary with time

Explanation:

Given the position of the particle

$y=kt^3$

Now, if we need to find the velocity then we need to differentiate it w.r.t. t

$v=\frac{dy}{dt}$

$\implies v=\frac{d}{dt} (kt^3)$

$\implies v=3kt^2$

Now , we also know that acceleration is rate of change of velocity

Therefore,

$a=\frac{dv}{dt}$

$\implies a=\frac{d}{dt} (3kt^2)$

$\implies a=6kt$

Therefore we can conclude that acceleration varies with time

Thus (c) is the correct option.