if the position vector of a particle is given by r vector=(4cos 2t)i cap + 4 sin 2t j cap +6t k cap m, calculate acceleration at t =π/4
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Given r = (4cos2t) i + (4sin2t) j + 6t k
Differentiate for once to get the velocity
v = (-8sin2t) i +(8cos2t) j + 6 k
Differentiate again th get acceleration
a = (-16 cos 2t) i +(-16 sin 2t ) j
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