If the position vectors of three consecutive vertices of a parallelogram are I+j+k,3j+5k,and 7i+9j+11k, then fourth vertex is
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Answer:
Let A(
a
)=i+j+k
B(
b
)=i+3j+5k
C(
c
)=7i+9j+11k
D(
d
) is to be determined
ABCD is a parallelogram so
2
1
(
b
+
d
)=
2
1
(
a
+
c
)
d
=
a
+
c
−
b
=8i+10j+12k−(i+3j+5k)
=7i+7j+7k=7(i+j+k)
Step-by-step explanation:
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