Question

if the position (x) of a particle with time 't' as x =2t³-t²+5. what acceleration will we at time t =2 sec.​

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Answer 1

Answer:

here's your answer

have a great day ahead

Answer 2

Answer:

Correct option is

C

3b

a

v=

dt

dx

=2at−3bt

2

⇒a=

dt

dv

=

dt

2

d

2

x

=2a−6bt

a

c

=0⇒2a−6bt=0

t=

3b

a