If the positions corresponding to the multiples of 5 in the English alphabet are replaced by symbols and that of multiples of 7 by digits, how many letters will be left?
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The English Alphabets are 26 in total.
positions of multiples of 5 which have to be removed : 5th, 10th, 15th, 20th,25th
positions of multiples of 7 which have to be removed : 7th, 14th, 21st.
so total number of alphabets which are to be removed : 8 (5+3)
Letters left after removing : 26-8 = 18
Ans = 18 letters
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