Math, asked by abcdefgh7117, 2 months ago

if the potato field is 4x² aera of pumpkin field is 5x²+x area of corn field is 36x²+6x aera of bean field is x⁴+x³-2x²+x-1 and area of tomata field is x³-3x²+3x-1 ​

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Answered by kiran12355
8

Step-by-step explanation:

area of potato field=4x^2

area of pumpkin field=5x^2+x

area of corn field=36x^2+6x

area of bean field=x^4+x^3-2x^2+x-1

area of tomato field=x^3-3x^2+3x-1

A) 1) potato field:

l=x

area=l*b

4x^2=x*b

b=(4x^2)/x

b=4x

2)pumpkin field:

area=side xside

5x^2+x=x*x

5x^2+x=x^2

x= -4x^2

side= -4x^2

3)corn field:

l=?,w=6x

area=l*w

36x^2+6x=l*6x

l=(36x^2+6x)/6x

l=6x+1

4)bean field:

l=x-1, w=?

area=l*w

x^4+x^3-2x^2+x-1=(x-1)*w

w=[x^4+x^3-2x^2+x-1]/(x-1)

5)tomato field:

l=x-1 ,w=?

area=x^3-3x^2-3x-1=w*(x-1)

w=[x^3-3x^2-3x-1]/(x-1)

B)perimeter of pumpkin field

=4*side=4*(-4x^2)= -16x^2

C)sides are half of pumpkin field= -2x^2

area of cucumber filed=side*side=4x4

D)total area of field=x=3

2(x+6x+x-1)+(6x+1)

=2(6*3+2*3-1)+(6*3+1)

=2(23)(19)

=874

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