Question

If the potencial diffrences are 30v and 25v.The resisitence is 5 omega.Then what is the measurment of electricity flow​

Answer 1

Answer:

electric current =6Q,5Q

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Answer 2

Step-by-step explanation:

question is confusing.

if PD = 30 THEN R= 5 then i= 30/5 = 6

if PD = 25 THEN R= 5 then i= 25/5 = 5

if at A POTENTIAL = 30 AND at B Potential = 25

then potential difference = 30-25 =5 v

i = 5/5 = 1 ampere