If the potential difference across a capacitor is doubled, what happens to: (a) the charge on the capacitor and (b) the energy stored in the capacitors.
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(a)Charge, C=Q/V
As C is constant and Q is proportional to V
Hence, charge also gets doubled
(b)Energy, E=1/2 CV²
Energy is directly proportional to
square of Potential Difference
Hence, E becomes four times.
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