if the potential difference between a wire of fixed resistance is doubled,by how much does the electric power increases?
Answers
Answered by
112
I hope you know this well known formula
Power = (Potential difference)^2 / Resistance
P = V^2 / R
For fixed resistance
P ∝ V^2
∴ If Potential difference is doubled then the power increases by 4 units.
Power = (Potential difference)^2 / Resistance
P = V^2 / R
For fixed resistance
P ∝ V^2
∴ If Potential difference is doubled then the power increases by 4 units.
Answered by
10
Answer:
4 times
Explanation:
Similar questions