Question

if the potential difference between the ends of a wire of fixed resistance is doubled by how much does the electric power increase​

Answer 1

Answer:

Electric power increases by a factor of 2 (doubles)

Explanation:

Given :

If Potential difference across the ends of the conductor of fixed resistance is doubled, by how much does the electric power increase,.

Solution :

We know that,

V = IR ( Voltage = Current flow × Resistance)

P = VI  (Power = Voltage × Current flow)

⇒ P = (IR)I = I²R  (Power = (Current flow)² × Resistance )

Initially , $R_{old}$ = R  ( Resistance (R) = R )

⇒ P = I² R

Then , R is doubled ⇒ $R_{new}$ = R' = 2R

⇒ $P_{new}$ = P' = I²(2R) = 2I²R = 2(I²R) = 2P

⇒ The power is doubled when resistance gets doubled,.