Question

If the potential difference between two points 2 cm apart in an electric field is 20 V, the electric

field intensity between these points will be

(a) 20 V/m (b) 40 V/m (c) 10 V/m (d) 10 V/cm​

Answer 1

Explanation:

10 V/cm

I think this is the answer

Answer 2

Answer:

Option (d) 10 V/cm

Electric field intensity is 10 volt/cm

Explanation:

Given that:

Potential difference (V) = 20 V

Distance between two points (d) = 2 cm

Suppose the Electric field intensity = E V/cm

We know the relation between Electric field intensity and potential difference;

$V = E \: . \: d \: volt \: ...equation(1) \\ E = \frac{V}{d} \: volt \: .{cm}^{ - 1}$

So we get the Electric field intensity (E);

$E = \frac{20}{2} \: volt \: .{cm}^{ - 1} \\ E = 10\: volt \: .{cm}^{ - 1}$

So, Electric field intensity is 10 volt/cm

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