Question

If the potential difference generated by a battery across a circuit of two bulbs, combined in
series, is 6 volts, and the potential difference at the first bulb is 2 volts, find out the potential
difference at the second bulb?

Answer 1

In series, total V=V1+ V2
:-) 6=2+V2
:-) V2=4
Hence, potential difference at second bulb is 4V

Answer 2

Explanation:

In series, total V=V1+ V2

:-) 6=2+V2

:-) V2=4

Hence, potential difference at second bulb is 4V