Question

.If the potential difference V applied across a conductor is increased to 2V with its temperature kept constant, free electrons in a conductor (i) remain the same (ii) become half of its previous value (iii) be double of its initial value (iv) become zero​

Answer 1

Answer:

(iii) double of the initial value

Explanation:

I = neA Vd     and V = i r

Vd ∝ I

I ∝ V

⇒  Vd ∝ I  ∝ v

Answer 2

The free electrons in a conductor become double of its initial value.

• According to the formula of potential,

        $V= k \frac{q}{r}$.

• Here, V is the potential of the conductor, k is a constant whose value is equal to 9 × 10⁹ Nm²C⁻², q is the charge of the electron whose value is 1.6 × 10⁻¹⁹C and r is the radius of the electron.
• As evident from the formula, potential of the conductor is directly proportional to the charge of the electron.
• Hence, if the potential is increased to double its value (2V), the number of electrons also doubles.