Question

If the potential due to a point
charge at a distance of 50 cm is
51.0 V, then the new potential if
the distance is increased by 3
times is.​

Answer 1

Answer:

Potential due to a point charge is

V = KQ/R

V1 = 1/R1

V2/V1 = R1/R2

V2 = R1/R2×V1

V2 = R1/R1^3×V1

V2 = (50/50^3) × 51

V2 = (1/50^2) × 51

V2 = (1/2500) × 51

V2 = 0.0204