If the potential energy in ground state of a hydrogen atom is considered to be zero, then find the total energy is first excited state
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Answer:
-6.8eV
Explanation:
Total energy in first excited state, n=2
= -13.6÷4
= -3.4 eV
This is the sum of 3.4eV(Kinetic energy) and -6.8eV(Potential energy)
Since potential energy in the first excited state is to be zero, a +6.8eV is added to the total energy ie all enrgy levels must be added with +6.8eV
Thus total energy in ground state becomes -13.6 + 6.8 = -6.8eV
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