Question

If the potential energy of a spring when
streched Through
a distance a is 25J.
then what is the amount of work done
on the same
spring so as to strech it by additional
distance 5a


​

Answer 1

Answer:

Correct option is

C

30 J

F=

2

1

kx

2

In the first case, F=10J is required to stretch the spring by length x

10=

2

1

kx

2

F is the force required to stretch the spring by an additional length x

F=

2

1

k(2x)

2

=4×10=40J

Therefore additional force required is 40−10=30J