Question

if the potential energy (PE) of hydrogen electron is -3.02 eV then in which of the following excited level is electron present .1.1st........2.2nd......3.3rd.......4.4th

Answer 1

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Answer 2

Answer:

The correct answer is option 2.

Explanation:

$E_n=-13.6\times \frac{Z^2}{n^2}ev$

where,

$E_n$ = energy of $n^{th}$ orbit

n = number of orbit

Z = atomic number

Given .$E_n=-3.02 eV$

For hydrogen atom ,Z = 1

n =?

$-3.02 eV=-13.6\frac{1^2}{n^2}$

n = 2.1 ≈ 2

The electron is present in first excited level that is in second shell.