Question

If the potential of .A capacitor having capacity 6f is increased from 10 v to 20 v, then increase in its energy will be

Answer 1

Answer:

E = 9 x 10∧-4 J

Explanation:

E = 1/2 C ( V2² - V1²)

E = 1/2x6x10x(400-100)

E = 9 x 10∧-4 J