Physics, asked by maitreyasingh7768, 1 year ago

If the power factor in an ac circuit changes from 1/3 to 1/9 then by what percent reactance will change(aproxx.) , if resistance remains constant?
1) increase by 200%
2) decrease by 200%

Answers

Answered by Fatimakincsem
6

The percentage increase is 200%.

Explanation:

cosφ = power factor = R/Z

Where "R" is resistance and Z" is impedence

and Z = √ R^2+X^2

Where X is reactance.

1/3 = R/Z = R √ R^2 + X1^2

9 = 1 + (X1/R)^2

(X1/R)^2 = 8

X1/R = 2 √2 = 2.82

X1 = 2.82 R

Now 1/9 = R/Z = R √R^2 + X2^2

81 = 1 + (X2/R)^2

(X2/R)^2 = 80

X2 / R = 8.944

X2 = 8.94 R

% increase = 8.94 R − 2.82 R /2.82 R  x  100 = 217 so approx 200 %

Hence the percentage increase is 200%.

Also learn more

A torch bulb is rated 5 v and 500 m.A calculate its 1)power 2) resistance 3) energy consumed when it is lighted for 4 hours ?

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Answered by Rkp28
5

Increases by 200%........

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