Question

if the power of 2MV delivered through a wire of resistance 40 ohm at 10 KV. calculate the percentage of power loss​

Answer 1

Answer:

80%

Explanation:

Given

P=power=2MV

R=Resistance=40ohm

V=Voltage=10KV

Now we know that Power P=VI

So,Current  I= P/V

I=2*10^{6}/1010^{3} =200A

Now power loss = Heat Produced

I^2R =(200)^2*40 =1.6*10^6 w

% of power loss =1.6*10^6/2*10^6 =0.8*100 = 80%