Question

If the power of a motor is 200 KW. at what speed can it raise a load of 40,000 N?​

Answer 1

Answer:

Te required speed is 5 m/s

Explanation:

Power P = 200 kW = 2 x 10⁵ W

Force = 40,000 N = 4 x 10⁴ N

Since load is constant

Power = Force x velocity

P = F x v

∴ speed v = P/F = 2 x 10⁵/4 x 10⁴

= 20 x 10⁴/ 4 x 10⁴

= 5 m/s