IF THE POWER OF YOUR SPECTACLE IS 1.5 D . FIND THE FOCAL LENGTH OF THE SPECTACLE ?
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Explanation:
f = 1/1.5 = 2/3 = + 0.67 m. The focal length is + 0.67m. The nature of lens is converging type or convex lens. The defect of the eye is Hyperopia or far-sightedness.
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