Question

if the present age of son and father are expressed by x and y respectively after ten years father will be twice as old as his son.Write the relation between x and y

Answer 1

Let the present age of son = x
Let the present age of father = y
After 10 years,
Age of son = x+10
Age of father = y+10
Equation = y+10 = 2(x+10)

Answer 2

Given:

The father is twice the age of the son after 10 years.

To Find:

The age expressed in a relationship

Solution:

Define x and y:

Let the son's age be x.

Let the father's age be y.

10 years later:

son = x + 10

father = y + 10

The father is twice the son's age:

y + 10 = 2(x + 10)

Simplify the equation:

y + 10 = 2(x + 10)

y + 10 = 2x + 20

y = 2x + 10

Answer: The relationship is y = 2x + 10