Question

If the present ages of A and B are in the ratio 9:4 and seven years hence,the ratio of their ages will be 5:3,then find their present ages

Answer 1

age of A= 9x
age of B=4x
after 7 yrs
ratio of their ages = 9x+7upon4x+7=5/3
27x+21=20x+35
27x-20x=35-21
7x=14
x=2
so age of A = 18yrs and that of B=8yrs

Answer 2

Solutions :-

Given :
The present ages of A and B are in the ratio 9 : 4
After seven years,
The ratio of their ages will be 5 : 3

Let the present age of A and B be 9x and 4x respectively.

According to the question,

$= > \frac{9x + 7}{4x + 7} = \frac{5}{3} \\ \\ = > 3( 9x + 7) = 5(4x + 7) \\ \\ = > 27x + 21 = 20x + 35 \\ \\ = > 27x - 20x = 35 - 21 \\ \\ = > 7x = 14\\ \\ = > x = \frac{14}{7} = 2$

Hence,
Present age of A = 9x = 9 × 2 = 18 years
Present age of B = 4x = 4 × 2 = 8 years

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✯ @shivamsinghamrajput ✯