Question

if the present ages of a and b are in the ratio 9;4 and seven year hence the ratio of the present ages 5;3 find present ages

Answer 1

Answer:

Let their ages be 9x and 4x.

By the problem,

9x+7/4x+7 = 5/3

3(9x+7) = 5(4x+7)

27x+21 = 20x+35

27x-20x = 35-21

7x = 14

x = 14/7

x = 2

A's age = 9x = 9*2 = 18

B's age = 4x = 4*2 = 8

Answer : A is 18 years old and B is 8 years old.

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Answer 2

Answer:

$\boxed{\sf The\:present\:age\:of\:a\:is\:18.}$

$\boxed{\sf The\:present\:age\:of\:b\:is\:8.}$

Step-by-step explanation:

Let their present age be x

Let “a” and “b” age be 9x and 4x

$\large\leadsto\mathtt\purple{Seven\:years\:hence:-}$

• Age of “a” = 9x + 7
• Age of “b” = 4x + 7

$\large\leadsto\mathtt\red{Equation:-}$

→ 9x+7/4x+7 = 5/3

= 3(9x + 7) = 5(4x+7)

= 27x + 21 = 20x + 35

= 27x - 20x = 35 - 21

= 7x = 14

= x = 14/7

= x = 2

$\large\leadsto\mathtt\purple{Putting\:the\:values:-}$

• Age of “a” = 9x = 9(2) = 18
• Age of “b” = 4x = 4(2) = 8

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