Question

If the present ages of A and B are in the ratio 9:5 anf seven years hence, the ratio of their ages will be 5:3,then find their present ages

Answer 1

Solutions :-

Given :
The present ages of A and B are in the ratio 9 : 5
After seven years,
The ratio of their ages will be 5 : 3

Let the present age of A and B be 9x and 5x respectively.

According to the question,

$= > \frac{9x + 7}{5x + 7} = \frac{5}{3} \\ \\ = > 3( 9x + 7) = 5(5x + 7) \\ \\ = > 27x + 21 = 25x + 35 \\ \\ = > 27x - 25x = 35 - 21 \\ \\ = > 2x = 14\\ \\ = > x = \frac{14}{2} = 7$

Hence,
Present age of A = 9x = 9 × 7 = 63 years
Present age of B = 5x = 5 × 7 = 35 years

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✯ @shivamsinghamrajput ✯

Answer 2

Solutions :-

We have,
The present ages of A and B are in the ratio 9 : 5
seven years hence, the ratio of their ages will be 5 : 3

Let the present age of A be 9x
And Age of B be 5x


Find the value of x :-

A/q


$= > \frac{9x + 7}{5x + 7} = \frac{5}{3} \\ \\ = > 3( 9x + 7) = 5(5x + 7) \\ \\ = > 27x + 21 = 25x + 35 \\ \\ = > 27x - 25x = 35 - 21 \\ \\ = > 2x = 14\\ \\ = > x = \frac{14}{2} = 7$

Answer :
Age of A = 9x = 9 × 7 = 63 years
Age of B = 4x = 5 × 7 = 35 years


Hope it helps :-)