If the present population of a town is X and it decreases at the rate of Y% per annum, find the population after Z years.
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Answer:
This will be negative compound interest.
so
so population after z years will be
x ( 1 - (y/100))^z
Step-by-step explanation:
let x = 100
y = 10 %
z= 2 years
Then after 2 years population will be
100 ( 1- (10/100)) ^ 2
100( 0.9)^2
100 * 0.81
81
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