Question

If the pressure and absolute temperature of 3 liters of a gas are doubled, its volume would be

Answer 1

Answer:

pata nahi hai chal nikal

Answer 2

Answer:

If the pressure and absolute temperature of 3 liters of a gas are doubled, its volume would be the same as the initial volume.

Explanation:

Given data says,

At the initial stage,

Pressure ⇒P = P₁

Temperature  ⇒ T = T₁

Volume V = 3L

Now at the final stage,

Pressure P is doubled,

⇒P₂= 2P₁

And Temperature T is doubled

⇒ T₂= 2T₁

From the combined gas law,

Volume V₂ can be calculated as follows:

⇒ $\frac{P_{1}V_{1} }{T_{1} } = \frac{P_{2} V_{2_{} } }{T_{2} }$

⇒$\frac{P_{1} 3L}{T_{1} } = \frac{P_{2}V_{2} }{T_{2} }$         ...........(1)

now by putting the value of P₂ and T₂ in (1),

⇒$\frac{P_{1}3L }{T_{1} } =\frac{2P_{1}V_{2} }{2T_{1} }$

⇒V₂= 3L

Thus when pressure and absolute temperature are doubled, the proportion remains the same. The new volume of the gas would be the same as the initial volume. The volume doesn't change.

Hence if the pressure and absolute temperature of 3 liters of a gas are doubled, its volume would be the same.