Question

If the pressure at a point is 1m of water, what will be it’s value in terms of m of oil? (Take, the specific gravity of oil to be 0.8)​

Answer 1

Answer:

Pressure at a point P is equal to ρgh, where ρ is the density and h is the height of the liquid column. Therefore, ρwater * 1 * g = ρoil * h * g, where h is the pressure in terms of m of oil. Thus, h = ρwater / ρoil = 1/0.8 = 1.25.

Answer 2

Answer:

The pressure at a point of 1m in water will be equal to 1.25m in the oil with a specific gravity of 0.8.

Explanation:

The pressure exerted by a column of liquid of height h and density ρ is given by hydrostatic pressure equation,

$P=$ρ×$g$×$h$

where,

$P=$pressure

ρ=density of the liquid

$g=$acceleration due to gravity

The terms which we are going to use in this question is,

$h$₁=1m

the density of water(ρ₁)=1$g/cm^{3}$

$h$₂=height in the oil

The density of oil(ρ₂)

=The density of water(ρ₁)× the specific gravity of oil(R)

ρ₂=ρ₁×R

ρ₂=1$g/cm^{3}$×$0.8=0.8g/cm^{3}$

As per the question,

1×$g$×$1m$=$0.8$×$g$×$h$₂

$h$₂$=10/8$$=5/4=1.25$

Hence, the pressure at a point of 1m in water will be equal to 1.25m in the oil with a specific gravity of 0.8.