Question

if the pressure of 1 mole of gas is reduced to 1 /4 then the volume of the gas will be what?​

Answer 1

Answer:

here is the best answer

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please find attached .

Answer 2

Let :

• Initial pressure of gas ( P₁ ) = P
• Initial Volume of gas ( V₁ ) = V

Given :

• Number of mole = 1 mole
• Pressure is reduced to (1/4) of original pressure
• Note - As we are not given any information about temperature we will assume that temperature remain constant.

To find :

Final volume of gas

Solution :

According to Boyle's law , Pressure of gas is inversely proportional to the volume of gas when temperature is constant

P ∝ (1/V)

$\sf \implies \dfrac{P_1}{P_2} \:=\:\dfrac{V_2}{V_1}$

Now , according to question,

• P₁ = P
• P₂ = (1/4) P₁ = (1/4)P
• V₁ = V

Putting these values in above equation

$\sf \implies \dfrac{ \: P \: }{ \dfrac{P}{4} } \:=\:\dfrac{V_2}{V}$

$\sf \implies \dfrac{ \: P \: }{ P} \times 4 \:=\:\dfrac{V_2}{V}$

$\sf \implies \: V_2 \: = \: 4V$

➝ Volume of pressure became 4 times the original

ANSWER :

4 times the original